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4 years ago

Solve each of the following equations for the variable "a" 1. a^2+ b^2 = c^2

Mathematics

1 answer:

8090 [49]4 years ago

4 0

Answer:

where are the question??????

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(b) Find the angle between u and v to the nearest degree.

yulyashka [42]

Question 1 (b)

$u \cdot v=11\\\\|u|=\sqrt{3^{2}+(-1)^{2}}=\sqrt{10}\\\\|v|=\sqrt{4^{2}+1^{2}}=\sqrt{17}$

So,

$\cos \theta=\frac{11}{\sqrt{10}\sqrt{17}}\\\\\theta=\cos^{-1} \left(\frac{11}{\sqrt{10}\sqrt{17}} \right) \approx \boxed{32^{\circ}}$

Question 2 (b)

$u \cdot v=22\\\\|u|=\sqrt{5^{2}+2^{2}}=\sqrt{29}\\\\|v|=\sqrt{4^{2}+1^{2}}=\sqrt{17}$

So,

$\cos \theta=\frac{22}{\sqrt{29}\sqrt{17}}\\\\\theta=\cos^{-1} \left(\frac{22}{\sqrt{29}\sqrt{17}} \right) \approx \boxed{8^{\circ}}$

6 0

2 years ago

Which of the follow tables do not show a linear function

valina [46]

C , i dont know if it’s right but it’s the only table with the same number on the bottom . and same number in general

6 0

3 years ago

Read 2 more answers

I need to know, the area of sector AOB is what fractional part of the area of circle O

sertanlavr [38]

We are given that triangle AOB

6 0

1 year ago

Perform the indicated operation. Be sure the answer is reduced.

Morgarella [4.7K]

The answer is: $k^{2} /2
$
The explanation is shown below:
1. You have the following expression given in the exercise above:
$( 4k^{2}) /(2k+3)(2 k^{2} -5k-12)/(8k-32)
$
2. By applying the distributive property, you obtain:
$(8k^{4}-20k^{3}-48k)/(16k^{2} -40k-96)$
3. Now, you must factor $k^{2}$ in the numerator and $2
$ in the denominator:
$k^{2}(8 k^{2} -20k-48)/2(8 k^{2} -20k-48)$
4. Simplify:
$k^{2} /2$

8 0

3 years ago

PLZ HELP ME Round 8.87 to the nearest tenth.

stellarik [79]

Answer:

8.9

Step-by-step explanation:

examples of tenths: 0.88 1.05 23.456

5 0

4 years ago