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Dima020 [189]
4 years ago
6

Solve each of the following equations for the variable "a" 1. a^2+ b^2 = c^2

Mathematics
1 answer:
8090 [49]4 years ago
4 0

Answer:

where are the question??????

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Given h(x) = 4x + 5 solve for when h(x) = 9 .
Temka [501]

Answer:

3x = 5

Step-by-step explanation:

9x = 4x + 5

-4x -4x

3x = 5

8 0
3 years ago
Read 2 more answers
You have your heart set on buying a new car in 2 years. You invest $3,200 at 3.75% interest compounded continuously. How much mo
SCORPION-xisa [38]

<u>Answer:</u>

The available amount for the down payment of car and invested $3,200 at 3.75% interest compounded continuously is 3449.23$

<u>Explanation:</u>

We know final amount is given by  

Where,

A=P \times e^{r t}

A   =   final amount

P   =  initial principal balance = $3200

r    =   interest rate = 3.74%

t    =  number of time periods elapsed = 2 years

Substituting the values in the formula

r=\frac{3.75}{100}=0.0375

A=3200 \times e^{(0.0375 \times 2)}

We know, e = 2.72

So we get A = 3449.23$ which is the available amount for the down payment of car .

7 0
3 years ago
Help me please it is due tomorrow help with 2 or 3 just what in the boxes a nd who has what
artcher [175]
2640 is the answer for number 2.


4 0
3 years ago
Read 2 more answers
Find the real numbers x&amp;y so that (x^2+2xy)+i(y-1) = (x^2-2x+2y) - i(x+y)​
Mkey [24]

In order for two complex numbers to be equal, their real and imaginary parts must match up.

So if

<em>x</em> ² + 2<em>xy</em> + <em>i</em> (<em>y</em> - 1) = <em>x</em> ² - 2<em>x</em> + 2<em>y</em> - <em>i</em> (<em>x</em> + <em>y</em>)

then

<em>x</em> ² + 2<em>xy</em> = <em>x</em> ² - 2<em>x</em> + 2<em>y</em>

and

<em>y</em> - 1 = -<em>x</em> - <em>y</em>

<em />

Solve for <em>x</em> and <em>y</em> : the first equation gives

<em>x</em> ² + 2<em>xy</em> = <em>x</em> ² - 2<em>x</em> + 2<em>y</em>

2<em>xy</em> = 2<em>y</em> - 2<em>x</em>

and the second gives

<em>y</em> - 1 = -<em>x</em> - <em>y</em>

2<em>y</em> = 1 - <em>x</em>

Substitute this into the first equation:

<em>x</em> (1 - <em>x</em>) = (1 - <em>x</em>) - 2<em>x</em>

<em>x</em> - <em>x</em> ² = 1 - 3<em>x</em>

<em>x</em> ² - 4<em>x</em> + 1 = 0

<em>x</em> = 2 ± √3

Then

<em>x</em> = 2 - √3   ==>   <em>y</em> = (-1 + √3)/2

<em>x</em> = 2 + √3   ==>   <em>y</em> = (-1 - √3)/2

both of which make both sides of the equation (2 - √3) + <em>i</em> (√3 - 3)/2.

3 0
3 years ago
Of the four expressions presented here, which two are equivalent? Expression I: 19n Expression II: 4n + 9 + n + 5n Expression II
lutik1710 [3]

Answer:

Expression II and Expression III

Step-by-step explanation:

4n + 9 + n + 5n = 10n + 9

add 4n + 5n + n = 10n

add the 9 after that which equals 10n + 9 which is equivalent to Expression III

4 0
4 years ago
Read 2 more answers
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