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Aloiza [94]
3 years ago
5

I need help with number 17 please, and show work. I keep getting different answers. 1

Mathematics
1 answer:
Alecsey [184]3 years ago
8 0
\frac{(x+1)(x-1)}{(x+1)(x-1)(x+1)} - \frac{2(x-1)}{(x+1)(x-1)(x+1)} +  \frac{3(x+1)}{(x+1)(x-1)(x+1)}

=\frac{x^2-2-2x+2+3x+3}{(x+1)(x-1)(x+1)}
= \frac{x^2+x+4}{(x+1)(x-1)(x+1)} is what I got.
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\boxed{\bold{2\left(3x-1\right)\left(2x+3\right)}}

\bold{----------------------------------}

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\bold{2\left(6x^2+7x-3\right)}

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\boxed{\bold{Eclipsed}}

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