Question

Whats the answer to that

Answer 1

Given a quadratic equation

$ax^2+bx+c=0$

The solutions are given by

$\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In your case,

$a=1,\quad b=3,\quad c=1$

So, the solutions are

$\dfrac{-3\pm\sqrt{9-4}}{2}=\dfrac{-3\pm\sqrt{5}}{2}$

So, the two solutions are

$x_1 = \dfrac{-3+\sqrt{5}}{2},\quad x_2=\dfrac{-3-\sqrt{5}}{2}$

And they are approximated by

$x_1\approx -0.38,\quad x_2\approx -2.62$