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Natali5045456 [20]
3 years ago
15

FAST ANSWER PLEASE THANKS

Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0

Answer:

Option (1).

Step-by-step explanation:

Given  functions are f(x) = \frac{1}{x} and g(x) = x - 2

(fog)(x) = f[g(x)]

By substituting g(x) in place of x in the function f(x),

f[g(x)] = \frac{1}{(x-2)}

Graph of the function f[g(x)] will have,

Vertical asymptotes : x = 2

Horizontal asymptotes : y = 0

And no oblique asymptotes.

Out of four options graph number (1) matches the given characteristics of the function.

Therefore, graph (1) will be the answer.

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Ella completed 3/8 of a puzzle during recess on Tuesday. Joy completed two six of the same puzzle during recess on Wednesday. ho
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Well u have to make the denominator the same so u multiply 3/8 by 3 and get 9/24, then multiple 2/6 by three and get 8/24. Add them, 9/24+8/24 and u get 17/24
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Richard is asked to spray wash the exterior of a building that is shaped like a cube. The building has a side length of 7 meters
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Answer:d

Step-by-step explanation:

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Which statement best describes how to determine whether f(x) = 9 - 4x^2 is an odd function?
OverLord2011 [107]

Answer:

Which statement best describes how to determine whether f(x) = 9 - 4x^2 is an odd function?

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2 years ago
for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b
marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

               ⇒    300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

                                                = 101/2 (300+100)

                                                = 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4        

7 0
1 year ago
A store sells bread and milk. On Tuesday, 3 loaves of bread and 2 litres of milk were sold for €6.25. On Thursday
chubhunter [2.5K]

Equation is 4b + 5m = €10.90, and values of b and m are €1.35 and €1.1 respectively.

Step-by-step explanation:

  • Step 1: Find equation for Thursday's sales.

Given b = price of a loaf of bread and m = price of one liter of milk

Total sales = €10.90

Equation ⇒ 4b + 5m = €10.90

  • Step 2: Find the values of b and m.

3b + 2m = 6.25 ----- (1)

4b + 5m = 10.90 ---- (2)

Multiply eq(1) by 5 and eq(2) by 2 to make coefficients of m equal.

15b + 10m = 31.25

8b + 10m = 21.8

Subtract eq(2) from eq(1)

⇒ 7b = 9.45

⇒ b = 9.45/7 = €1.35

Substitute for b and find m using eq(1).

⇒ 3 × 1.35 + 2m = 6.25

⇒ 4.05 + 2m = 6.25

⇒ 2m = 2.2

∴∴ m = 2.2/2 = €1.1

8 0
3 years ago
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