Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,


![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)



meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
120$ will probally be it hope this helped
We are given this

write it as the difference of cubes

use the formula for the difference of cubes

Now use the formula for the difference of squares as 
