Answer:
example, such as you could cover 3 miles in distance 1 a a quantity that has both a magnitude/size speed limits on the roads and more junctions in 3 velocities for each section: A = 200 m / 50 s = front stops suddenly. gravitational potential and back as the roller 3 a mass = 1000 m3 × 1000 kg/m3 = 1 × 106 kg.
Step-by-step explanation:
Answer:
0.28125
Step-by-step explanation:
1 mile 0.1875
1/2 mile 0.09375
Add together and you get your answer!
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Answer:
75°
Step-by-step explanation:
∠ESK is the supplement of ∠EDK, so is 100°. ∠ESD = 1/2·arc ED, so is 25°. Since ...
∠ESK = ∠ESD + ∠DSK
you have ...
100° = 25° + ∠DSK . . . . fill in known values
75° = ∠DSK . . . . . . . . . . subtract 25°
_____
Regarding opposite angles of an inscribed quadrilateral
Chord EK divides the 360° circle into two arc: major arc EDK and minor arc ESK. The sum of those arcs is 360°. Each of the inscribed angles that intercepts those arcs has half the measure of the arc. That is, ∠ESK intercepts arc EDK, so has half its measure. Likewise, ∠EDK intercepts arc ESK, so has half its measure. The sum of those opposite angles will be the sum of half the measures of the arcs, so half the sum of the arcs, or 1/2·360° = 180°.
This is why we can say ∠ESK is the supplement of ∠EDK.
STEP 1:
convert gallons to cups & calculate total number of cups
1 gallon= 16 cups
= 8 gallons * 16 cups/gallon
= 128 cups total
STEP 2:
calculate total cups estimated for 20 guests
= 20 guests * 2 cups/guest
= 40 cups needed for guests
STEP 3:
subtract the difference between step 1 and step 2 to find leftover punch
= 128 cups - 40 cups
= 88 cups leftover
OR
GALLONS LEFTOVER
= 88 ÷ 16 cups/gallon= 5 1/2 gallons
ANSWER: There will be 88 cups or 5 1/2 gallons of punch leftover.
Hope this helps! :)
36 will be the answer for x