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3 years ago

I need help not sure how to answer this

Mathematics

2 answers:

Alja [10]3 years ago

6 0

Answer33

Step-by-step explanation:

otez555 [7]3 years ago

3 0

Answer:

D. 123

Step-by-step explanation:

If angle BAC is 57, then so is the one opposite to it, angle BCD. So together, they would make 114 degrees (57 +57).

If there are a total of 360 degrees in a rhombus and 114 are taken up, then that means we have 246 degrees left (360 - 114 = 246).

These 246 degrees are equally shard by angles B and D. Therefore, we just have to divide by 2 to get the answer:

246 / 2 = 123. And that's your answer!

Hope this helps! Please rate this answer and mark it as Brainliest! :)

Have an awesome day! :)

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<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%

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To find the vertical asymptote, equate the denominator to zero and solve for x.

$x^4+x^3-4x^2-4=0$

This implies that;

$x= -2.69,x=1.83$

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

$\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

$\Rightarrow x^2-4=0$

$x^2=4$

$x=\pm \sqrt{4}$

$x=\pm2$

The roots are $x=-2,x=2$

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

$x=0$ into the function

$f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}$

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e) to find the horizontal asypmtote, we take limit to infinity

$lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

The horizontal asymtote is $y=0$

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

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I need help not sure how to answer this​

I need help not sure how to answer this