Question

Solve for x. 2x² +21x-61 = (x+7)² Please

Answer 1

Answer:

$x = \frac{-7 +\sqrt{489} }{2}$

$x = \frac{-7 - \sqrt{489} }{2}$

Step-by-step explanation:

2x² +21x-61 = (x+7)²

expand

2x² + 21x - 61 = x² + 14x +49

move everything to one side

x² + 7x - 12 = 0

use quadratic formula

$x = \frac{-b +- \sqrt{b^{2}-4ac } }{2a}$

plug in the values

$x = \frac{-7 +- \sqrt{7^{2}-4(1)(-110) } }{2(1)}$

solve

$x = \frac{-7 +- \sqrt{49-4(1)(-110) } }{2}$

$x = \frac{-7 +- \sqrt{49 + 440 } }{2}$

$x = \frac{-7 +- \sqrt{489} }{2}$

Answer 2

After you rewrite the equation, identify the coefficients , substitute the coefficients and simplify the expression you’ll be left with 489