Answer: answer
explain : [One glucose and oxygen ]
<h2>Active and Passive Immunity</h2>
Explanation:
- Immunity can be obtained distinctly and Recovery from clinical tetanus doesn't bring about assurance against future disease by <em>active or passive immunization</em> and recovery from the clinical<em> for example, immunization, immunoglobulin treatment, or move of maternal antibodies through the placenta</em>
- Active inoculation stimulates the <em>immune system to deliver antibodies against a specific irresistible specialist</em>
- <em>Active immunity</em> can emerge normally, as when somebody is presented to a pathogen.<em> For example,</em> a person who recuperates from a first instance of the measles is <em>insusceptible to advance immunity</em>
Jan Ingenhousz discovered photosynthesis
Answer:
The answer to your question is...
Explanation:
Robert Hooke and Anton van Leeuwenhoek.
Answer:
The probability of producing a round and green plant from this cross is 3/16
Explanation:
This question involves two distinct genes coding for seed shape and seed colour. In the seed shape gene, allele for round seeds (R) is dominant over allele for wrinked seeds (r), while in the seed colour gene, allele for yellow seed (Y) is dominant over allele for green seeds (y).
A truebreeding plant means that the plant possesses homozygous genotype. Hence, a truebreeding pea plant with round and green seeds will have genotype: RRyy while true-breeding pea plant with wrinkled and yellow seeds will have genotype: rrYY. These two parents will produce F1 offsprings with genotype: RrYy (heterozygous).
When the F1 offsprings are self-crossed (RrYy × RrYy), the following allelic combinations of gametes will be produced by each F1 parent: RY, Ry, rY, ry
Using these gametes in a punnet square (see attached image), 16 possible F2 offsprings with a phenotypic ratio 9:3:3:1 will be produced
9- Round yellow offsprings (R_Y_)
3- Round green offsprings (R_yy)
3- Wrinkled yellow offsprings (rrY_)
1- Wrinkled green offsprings (rryy)