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miv72 [106K]
3 years ago
6

Help i dont understand Pls Help :( Given h(x)=4x-4h(x)=4x−4, solve for xx when h(x)=0h(x)=0.

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0

Answer:

x=1

Step-by-step explanation:

So when it's h(5)= whatever equation you all the x in the equation to 5 and solve. When it says h(x)=0, it's asking you to find x for the equation to equal 0.

It's easy! all you have to do is set the equation to 0

so 4x-4=0

add 4 from both sides

4x = 4

divide

x=1

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<h2>Greetings!</h2>

Answer:

t = \frac{3}{2}

Step-by-step explanation:

First, you need to complete the -3 + 1 and then expand the brackets

-3 + 1 = -2

7t -2 - (-2) = -3(1 - 3t)

Now expant the -3(1 - 3t) bracket

-3 * 1 = -3

-3 * -3t = 9t

7t - 2 - -2 = 9t - 3

The two negatives turn positive:

7t - 2 + 2 = 9t - 3

7t = 9t - 3

Move the -3 over to the oposite side, and also move the +7t over to the +9t, making it a negative:

3 = 9t - 7t

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Divide both sides by 2:

t = \frac{3}{2}

So the value of t is \frac{3}{2}


<h2>Hope this helps!</h2>
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4 years ago
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Nat2105 [25]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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