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1 year ago

What are the domain and range of the function (x)=3/4x+5?

Mathematics

1 answer:

solmaris [256]1 year ago

7 0

Answer: Option (1)

Step-by-step explanation:

The domain and range of all linear functions is the set of real numbers.

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What is the word for: The solid, liquid, or gas through which sound travels:

mash [69]

Answer:

I believe your answer would be Soundis

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2 years ago

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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

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2 years ago

Find 5 solutions to the question. Y=-1.5x+2

Black_prince [1.1K]

Answer:

☆< 《HOPE IT WILL HELP YOU》>☆

Step-by-step explanation:

Y=1.5x+2

y=1.5 (1) +2

y=1.5+2

y=3.5

y=1.5(2)+2

y=3+2

y=5

y=1.5 (3)+2

y=4.5+2

y=6.5

y=1.5 (4)+2

y=6+2

y=8

y=1.5 (5)+2

y=7.5+2

y=9.5

<h2>please mark my ans as BRAIN LIST</h2>

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3 years ago

Find the commission. Earning Commission | sales = $530 | commision rate = 3% | commision = ?

sergij07 [2.7K]

Answer:

$15. 90

Step-by-step explanation:

3% of 530= 15.9

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2 years ago

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Is this set closed or not closed under the operation ? Negative integers under multiplication

Romashka [77]

The set is not closed

Example:

-4 * -3 = 12 this is not a negative integer

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2 years ago