Question

Can someone please help me out on these few questions?

Answer 1

Answer:

See Below

Step-by-step explanation:

1.

$(2m+4)^{2} \\= (2m + 4)(2m + 4) \\= (2m)(2m) + (4)(2m) + (2m)(4) + (4)(4) \\= 4m^{2} + 8m + 8 m + 16 \\= 4m^{2} + 16m + 16$

2.

$(2x + 1)( x - 3) \\= (2x)(x) + (1)(x) + (2x)(-3) + (1)(-3) \\= 2x^{2} + x - 6x -3 \\= 2x^{2} -5x -3$

3. The missing term is 7x^2 * 3

$(7x^{2})(3)\\= 21x^{2}$

4. The terms in the final polynomial are 42x^2, 9 and 42x^4. Because the missing term is 21x^2 and the terms in the final polynomial includes all the blocks

Answer 2

Answer:

For the 3rd picture, the answer is 21x^2.

Step-by-step explanation:

Well, on the top row, you have 7$x^{2}$ times 3. That's 21$x^{2}$. So, for the second row, it's the same thing. And, 7*3=21 and you have $x^{2}$ left over. So, 21+$x^{2}$ = 21$x^{2}$

Hope this helped you out! (: