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valentinak56 [21]
2 years ago
13

URGENT PLEASE HELP!!

Mathematics
2 answers:
sladkih [1.3K]2 years ago
7 0

Answer:

your ans is 282475249

Step-by-step explanation:

give this answer brilliant

kaheart [24]2 years ago
5 0

Answer:

282475249

Step-by-step explanation:

frist simplify numbers in bracket
=7^2 (7^4 * 7^4)
=7^2 (7^8)
=7^10
=7*7*7*7*7*7*7*7*7*7
=282475249

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How is multiplying two mixed numbers like multiplying two proper fractions
Inga [223]
I think this is it but not sure sorry 

4 0
3 years ago
Can you help me please ? im not able to fiqure it out
kakasveta [241]

(7^5 * 7^3)^4 * 7^-2 / 7^-7 * 7^20

= (7^8)^4 * 7^-2 / 7^(-7 + 20)

= 7^32 * 7^-2 / 7^13

= 7^(32 - 2) / 7^13

= 7^30 / 7^13

= 7^(30 - 13)

= 7^17

5 0
3 years ago
Question 2 (Multiple Choice Worth 1 points)
Alexxx [7]
I think it is d. the last one
6 0
4 years ago
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d1i1m1o1n [39]

Answer:

(6,300)

Step-by-step explanation:

bro it removed my answer

it would be (6,300)

it would be that because that is where the two lines intersect, so the solution is the intersection point.

And it would be all of the above because:

a) when the the x value is at 6, that is the number of weeks, and the intersection point is on there.

b) as you can see after the 6 week period, lane's values are larger than Landry's

c) you can see Landy has a better rate

8 0
3 years ago
1. What was the approximate longitude of the Ottoman Empire’s easternmost boundary in 1566?
Anna35 [415]
<span>50°13' East In 1566, the easternmost border of the Ottoman Empire was near the location of the modern day City of Al Khobar along the coast of the Persian Gulf. The latitude of the city is approximately 26°13' North, 50°13' East. This is significantly further east than the Ottoman Empire's border in 1520 which didn't even approach the Persian Gulf and was approximately 42° East.</span>
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3 years ago
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