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Mumz [18]
4 years ago
15

The temperature was 54 at 7:00 a.m. At 3:00 p.m. on the same day, the temperature was 82. What is the rate of change in temperat

ure during this time?
Mathematics
1 answer:
vampirchik [111]4 years ago
4 0

Answer:

The rate of change was 3.5 degrees / h.

Step-by-step explanation:

In order to calculate the rate of change we need to divide the variation of temperature by the variation of time. Since the time is given to us in a 12 h format (am/pm), we first need to convert it to 24 h. To do that we sum the time that is "pm" by 12, we have:

time2 = 3 + 12 = 15

Therefore the rate of change in temperature is:

rate = variation of temp / variation of time

rate = (temp final - temp init) / (time final - time init)

rate = (82 - 54) / (15 - 7) = 28 / 8 = 3.5 degrees / h

The rate of change was 3.5 degrees / h.

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Given the function f(x) = 5^x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average r
Masteriza [31]
Part A)

f(x) = 5^x
f(0) = 5^0
f(0) = 1
----------
f(x) = 5^x
f(1) = 5^1
f(1) = 5
----------
f(x) = 5^x
f(2) = 5^2
f(2) = 5*5
f(2) = 25
----------
f(x) = 5^x
f(3) = 5^3
f(3) = 5*5*5
f(3) = 125

-------------------

Rate of change for section A = (f(1) - f(0))/(1 - 0)
Rate of change for section A = (5 - 1)/(1 - 0)
Rate of change for section A = 4/1
Rate of change for section A = 4

Rate of change for section B = (f(3) - f(2))/(3 - 2)
Rate of change for section B = (125 - 25)/(3 - 2)
Rate of change for section B = 100/1
Rate of change for section B = 100

================================================

Part B)

From part A) above, we found,

Rate of change for section A = 4
Rate of change for section B = 100

Which means that section B's rate of change is 25 times greater (since 100/4 = 25, or 25*4 = 100)

Answer for part B: 25

================================================

Extra:  Explain why one rate of change is greater than the other.

The rate of change for section B is larger because the exponential function is growing faster as x increases. This is shown visually by the sharper and steeper incline as the function curve goes upward. The function starts off with relatively slower growth but it accelerates in speed. 

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Step-by-step explanation:

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