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bulgar [2K]
3 years ago
9

Proportions, assist me please! ​

Mathematics
1 answer:
Anit [1.1K]3 years ago
6 0

Step-by-step explanation:

w =  \frac{1}{2}  {x}^{2} y \\ (2)w =  \frac{1}{2}  {x}^{2} y(2) \\ 2w =  {x}^{2} y \\  \frac{2w}{ {x}^{2} }  =   \frac{{x}^{2} y}{ {x}^{2} } \\ \frac{2w}{ {x}^{2} } = y

<h3>Answer:</h3>

y =  \frac{2x}{ {x}^{2} }  \\

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Word problem-in a movie script time traveler wanted to save his wife who died the same year. The couple was the dam age. However
drek231 [11]

Represent Age of Time Traveler =========> X

Solve:

x = 3(x - 20 )


Step 1: Simplify Both sides of equation:

x = 3(x - 20 )

x = (3) (x) + (3) ( - 20 ) (Distribute ):

x = 3x + - 60

x = 3x - 60


Step 2: Subtract 3x from both sides:

x - 3x = 3x - 60 - 3x

- 2x = - 60


Step 3: Divide both sides by -2:

- 2x / - 2 = - 60 / - 2

x = 30



Answer: Our Time Traveler is 30 years old.




Hope that helps : )




5 0
3 years ago
A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha
8_murik_8 [283]
To model this situation, we are going to use the decay formula: A=Pe^{rt}
where 
A is the final pupolation
P is the initial population 
e is the Euler's constant
r is the decay rate 
t is the time in years

A. We know for our problem that the initial population is 1,250, so P=1250; we also know that after a year the population is 1000, so A=1000 and t=1. Lets replace those values in our formula to find r:
A=Pe^{rt}
1000=1250e^{r}
e^{r}= \frac{1000}{1250}
e^{r}= \frac{4}{5}
ln(e^{r})=ln( \frac{4}{5} )
r=ln( \frac{4}{5} )
r=-02231

Now that we have r, we can write a function to model this scenario:
A(t)=1250e^{-0.2231t}.

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C. 
- The function is decreasing
- The function doe snot have a x-intercept 
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0: 
A(0)=1250e^{(-0.2231)(0)
A_{0}=1250e^{0}
A_{0}=1250
- Over the interval [0,10], the function will have a minimum at t=10:
A(10)=1250e^{(-0.2231)(10)
A_{10}=134.28

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: m= \frac{A(0)-A(10)}{10-0}
where 
m is the rate of change 
A(10) is the function evaluated at 10
A(0) is the function evaluated at 0
We know from previous calculations that A(10)=134.28 and A(0)=1250, so lets replace those values in our formula to find m:
m= \frac{134.28-1250}{10-0}
m= \frac{-1115.72}{10}
m=-111.572
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0
3 years ago
If US $1.00 is equivalent to EC $ 2.70, how much in US would one get from EC 297.00?
Vedmedyk [2.9K]
NEEED POINTS ..





xx ‘zmsms
4 0
3 years ago
In this question, all lengths are in centimetres.
JulsSmile [24]

Answer:

Step-by-step explanation:

AB/AC =1/2

(3x-4)/(2x+12)=1/2

2(3x-4) = 1(2x+12)

6x-8=2x+12

4x=20

X=5

AC/BC =3x-4/7x-2=22/33=2/3

AB/AC=3x-4/7x-2=22/33=2/3

AB/AC=3x-4/2x+12

6x-8=2x+12

You would get 4/5 still trying to work out the last mark

3 0
3 years ago
10 points each question :)<br> Please help, I don't really understand these :-(
stellarik [79]
Answer is b
you welcom and i hope this helps
8 0
3 years ago
Read 2 more answers
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