The answer is either b or c
Answer:
(f o g) (x) = 36x² + 3
(g o f) (x) = 6x² + 18
Step-by-step explanation:
f(x) is x² + 3
g(x) is 6x
(f o g) (x) means for all xs in f replace it with g(x) or 6x
(f o g) (x) = (6x)² + 3 - see 6x is in place of x and 6x is g(x)
(f o g) (x) = 36x² + 3
(g o f) (x) = 6(x² + 3)
(g o f) (x) = 6x² + 18
Answer:
B. 1/m¹⁸
Step-by-step explanation:
To simplify the equation, we start with the values inside the brackets.
Therefore m⁻¹m⁵ results to m⁴.
This is because the sign between the m⁻¹ and m⁵ is multiplication, and when multiplying figures that have a similar base, we add the indices.
that is, -1+5=4
then we divide m⁴ by m⁻², that is, m⁴/m⁻²=m⁶
To divide figures that have the same base we subtract the powers.
That is, 4-(-2)=6
the resulting expression from inside the brackets will be (m⁶)³ which results to m⁻¹⁸ which is the same as 1/m¹⁸
Remember the order of operations.
Dividing fractions means multiplying a reciprocal.
3÷1/3=3×3/1=9
9-9+1=1
1 is your answer.
:)
Step-by-step explanation:
With reference to the regular hexagon, from the image above we can see that it is formed by six triangles whose sides are two circle's radii and the hexagon's side. The angle of each of these triangles' vertex that is in the circle center is equal to 360∘6=60∘ and so must be the two other angles formed with the triangle's base to each one of the radii: so these triangles are equilateral.
The apothem divides equally each one of the equilateral triangles in two right triangles whose sides are circle's radius, apothem and half of the hexagon's side. Since the apothem forms a right angle with the hexagon's side and since the hexagon's side forms 60∘ with a circle's radius with an endpoint in common with the hexagon's side, we can determine the side in this fashion:
tan60∘=opposed cathetusadjacent cathetus => √3=Apothemside2 => side=(2√3)Apothem
As already mentioned the area of the regular hexagon is formed by the area of 6 equilateral triangles (for each of these triangle's the base is a hexagon's side and the apothem functions as height) or:
Shexagon=6⋅S△=6(base)(height)2=3(2√3)Apothem⋅Apothem=(6√3)(Apothem)2
=> Shexagon=6×62√3=216
