The relation between number of people who receive a newspaper on day d of a delivery schedule is given by:
n(d) = 4.3 d - 1
On first day , i.e d =1
n = 4 × 3 -1
= 12 -1
= 11
For, d =2
n(d) = 4 × 3 × 2 -1
= 24 -1
= 23
for , d=3
n(d) = 4 × 3 × 3 - 1
= 36 -1
= 35
When , d = 4
n(4)= 4 × 3 × 4 - 1
= 48-1
= 47
n(5) = 4×3×5 -1
= 60 -1
= 59
As you can see the pattern ,the number of people who receives newspaper starting from day = 1,2,3,4,5,6,7.... is 11,23,35,47,59,71,83,.......
As the given sequence is Airthmetic progression , having , a = 11
d = 23 -11= 12,
<em> = </em>11 +12 × (n-1)
= 11 + 12 n - 12
= 12 n - 1
= 4 × 3 × d - 1 →→n is replaced by d