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xenn [34]
2 years ago
12

PLEASE HELP ME!! please explain your answer so I know how to do it next time! The question is number 7

Mathematics
1 answer:
natita [175]2 years ago
5 0

Answer:

Step-by-step explanation:

How to find speed-

Use formula s= d/t

dist.= 50 m

t=2.25 hrs

S=22.2

(I used calculator u can too)

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Sladkaya [172]

(2, 0) (2, 7) assuming that Y can equal anything.

7 0
3 years ago
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Round 27346 to 2 significant figures i need a step by step expansion
belka [17]

Answer:

27000

Step-by-step explanation:

We want to round 27346 to 2 significant figures.

Now, the number already has 5 significant figures, so to reduce it to 2 sig figures, we will have to reduce the 3 digits from the right to zero so that we can have just 2 significant figures by approximating.

Thus, 3 is less than 5 and so 7 cannot increase. Thus, we will have 27000 as the number when reduced to 2 significant figures.

5 0
3 years ago
Elizabeth states, "if the diagonals of a parallelogram are congruent, then the parallelogram is a rhombus." decide if her statem
Igoryamba
Hello,
Answer B: false

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8 0
3 years ago
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Question in attachment​
denis-greek [22]

Answer:

(a) x + y = 63 OR 3x = 63

(b) 21

(c) 42

Step-by-step explanation:

Let Vijay's age be x and Ajay's be y.

Ajay is <u>twice</u> as old as Vijay

==> Ajay's age = 2 × Vijay's age

==> <u>y = 2x</u>

<h3>(a)</h3>

<u>Sum</u> of their ages = 63

==> x + y = 63

<em>Substituting</em><em> </em><em>2</em><em>x</em><em> </em><em>for</em><em> </em><em>y</em><em>:</em>

==> x + 2x = 63

==> 3x = 63

<h3>(b)</h3>

<em>Solving the above-obtained equation:</em>

<u>==> x = 21</u>

<h3>(c)</h3>

Ajay's age = 2 times that of Vijay

==> y = 2x

==> y = 2×21

<u>==> y = 42</u>

6 0
2 years ago
One number is 6 more than anouther number. the sum of their squares is 90
Flura [38]
Let x = greater number
      y = smaller  number

(1) x = y + 6&#10;
(1) y = x-6

(2) x^{2} + y^{2} = 90
We'll substitute y in (1) to (2)
(2) x^{2} +  (x-6)^{2} = 90
     x^{2} +  (x^{2} - 12x + 36) = 90
     x^2 + x^2 -12x + 36 - 90 = 0
     2x^2 - 12x -54 = 0&#10;
     2(x^2 - 6x - 27) = 0
     2(x - 9)(x + 3) = 0
 x - 9 = 0        or      x + 3 = 0
      x = 9                        x = -3
and
 y = x - 6                  y = x - 6
 y = 9 - 6                  y = -3 - 6
 y = 3                        y = -9

Therefore, the two numbers can be 9 and 3 or -3 and -9.

      
6 0
3 years ago
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