Question

The given line segment has a midpoint at (3, 1).

Answer 1

Answer:

A.y =1/3 x

Step-by-step explanation:

Answer 2

Let A(2,4) & B(4,-2)

The slope of AB = m = $\frac{-2-4}{4-2}= \frac{-6}{2}=-3$

Now we know the slope of a line perpendicular is -1/m

So slope of perpendicular line to AB shall be m = $\frac{-1}{-3}= \frac{1}{3}$

Hence the equation of line shall be

$y=\frac{1}{3}x+c$

Now this line passes through (3,1)

Substituting in the equation we get

$1= \frac{1}{3}(3)+c$

1=1+c

c=0

Hence the equation of the line perpendicular to AB is

$y=\frac{1}{3}x$