The answer to your question would be 4hr I think
Well the formula to solve for the volume of a right circular cylinder would be, V=πr2h. For the radius, the number inserted into the formula would be half of the diameter measurement. Therefore, the radius would be 3 m. As for the height measurement, the number would remain the same of 5m. Once all figures are applied to the formula: V=π(3^2)(5), the answer could then be rounded either to the tenths or hundredths depending on what your teacher asks for. The answer in the end would come down to approximately 141.37 meters cubed.
Answer:
Reasons:
1. Given
2. Given
3. Definition of bisector
4. Reflexive property
5. SAS Congruence
Step-by-step explanation:
This is quite easy to solve. All that you're expected to do is to complete the reason that justifies each statement given in the two-column proof.
Let's complete the proof as follows:
1. Statement: 
1. Reason: Given
We know this statement is true because we are given in the question.
2. Statement: FG bisects <DFE
2. Reason: Given
We also know this because we are told so in the question, as shown in the diagram given.
3. Statement: 
3. Reason: Definition of bisector
We know this because an angle bisector divides an angle into two equal halves. Therefore, the definition of bisector justifies why it was stated that
4. Statement: 
Reason: Reflexive property.
5. Statement: ∆DFG 
EFG
5. Reason: SAS Congruence
Two sides (DF and FG) and an included angle (angle 1) of ∆DFG is congruent two corresponding sides (EF and FG) and an included angle (angle 2) of ∆EFG. Therefore, ∆DFG EFG by the Side-Angle-Side (SAS) Congruence Theorem.
Answer:
A) The best way to picture this problem is with a probability tree, with two steps.
The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.
The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.
If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.
If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.
B) So a person can have a red marble and a blue marble in two ways:
1) Picking the red first and the blue last
2) Picking the blue first and the red last
C) P(R&B) = 3/5 = 60%
Step-by-step explanation:
C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5
Answer:
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