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7nadin3 [17]
3 years ago
6

Find the equation of the line whose slope is -3/4 which passes through the point of (0,3)

Mathematics
1 answer:
padilas [110]3 years ago
8 0
Equation: y = mx + c

Given m = -3/4
y = -3/4 x + c

At (0,3)
 3 = -3/4 (0) + c
c = 3

Equation: 
y  = -3/4x + 3

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A coin is tossed 11 times. a) How many different outcomes are possible? b) How many different outcomes have exactly 8 heads? c)
larisa86 [58]

Answer:

a) 2048

b)164

c)54

d) 11

Step-by-step explanation:

a) A coin has two faces.

Outcome possible =2^11= 2048

b) 8 heads possible outcome = 11!/8!3! = 3971688/241/920= 164 ways

c)2 heads outcome= 11!/2!8!= 39716800/725760=54

d) 7 heads= 11!/7!6! =39716800/3628800 = 11

5 0
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1. Show your work to simplify the expression 0.5(8a +6b) a + 4b​
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Answer:

Using distribute property

0.5(8a)(a) + 0.5(6b)(a) + 4b

4a^2 + 3ab + 4b

Step-by-step explanation:

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A type i error is committed when
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Answer: Choice A) A true null hypothesis is rejected

In other words, if the reality is that the null is true but your research says otherwise, then you've committed a type i error.

A type ii error is when you fail to reject the null (basically "accepting" the null) while in reality the alternative is the true hypothesis.
3 0
4 years ago
A torus is formed by rotating a circle of radius r about a line in the plane of the circle that is a distance R (> r) from th
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Consider a circle with radius r centered at some point (R+r,0) on the x-axis. This circle has equation

(x-(R+r))^2+y^2=r^2

Revolve the region bounded by this circle across the y-axis to get a torus. Using the shell method, the volume of the resulting torus is

\displaystyle2\pi\int_R^{R+2r}2xy\,\mathrm dx

where 2y=\sqrt{r^2-(x-(R+r))^2}-(-\sqrt{r^2-(x-(R+r))^2})=2\sqrt{r^2-(x-(R+r))^2}.

So the volume is

\displaystyle4\pi\int_R^{R+2r}x\sqrt{r^2-(x-(R+r))^2}\,\mathrm dx

Substitute

x-(R+r)=r\sin t\implies\mathrm dx=r\cos t\,\mathrm dt

and the integral becomes

\displaystyle4\pi r^2\int_{-\pi/2}^{\pi/2}(R+r+r\sin t)\cos^2t\,\mathrm dt

Notice that \sin t\cos^2t is an odd function, so the integral over \left[-\frac\pi2,\frac\pi2\right] is 0. This leaves us with

\displaystyle4\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}\cos^2t\,\mathrm dt

Write

\cos^2t=\dfrac{1+\cos(2t)}2

so the volume is

\displaystyle2\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}(1+\cos(2t))\,\mathrm dt=\boxed{2\pi^2r^2(R+r)}

6 0
3 years ago
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Answer:

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60% of 60km

60/100

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36 km

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