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3 years ago

Write an equation of the line that passes through (3,2), and is perpendicular to the line

Mathematics

1 answer:

frutty [35]3 years ago

8 0

Step-by-step explanation:

step 1. perpendicular lines have negative reciprocal slopes

step 2. perpendicular to m = 1/3 is the slope m = -3/1 or m = -3

step 3. a line through (3, 2) with m = -3 is y - 2 = -3(x - 3)

step 4. y - 2 = -3x + 9

step 5. y = -3x + 11.

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Find the area of a square whose diagonal length is 32 CM

BigorU [14]

Answer:

512cm^2

Step-by-step explanation:

Let's imagine cutting the square down that diagonal. Now, we have two isosceles right triangles with a hypotenuse with length 32cm. Let's take one of those triangles for now and focus on it. Let's give the one of the legs of a triangle some length x. Since both legs are the same length, by the Pythagorean theorem:

$x^2+x^2=32^2\\\\2x^2=1024\\\\x^2=512\\\\x=\sqrt{512}$

Since this leg makes up one side of the square, we can use it to calculate the area of the square, which is just the side length squared:

$A=(\sqrt{512})^2 = 512$

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3 years ago

Write the solution of the inequality in set builder notation: 2(3p-11)>=-16

Dima020 [189]

The answer would be
p≥1

hope this helps :3

8 0

3 years ago

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Write an equivalent fraction of 4/5 with the denominater 25

Temka [501]

Answer:

20/25

Step-by-step explanation:

to get to a dinominator of 25, we have to multiply 5 by 5. so then we do 4 x 5 so now it is 20/25

4 0

3 years ago

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Amy was thinking of a number then divides by 2 then adds 11 and the answer was 12 what was the original number?

pashok25 [27]

Answer:

Step-by-step explanation:

Let x be the original number.

x/2 +11=12

Now solve for x

x=2

5 0

4 years ago

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Find the inverse of f informally. verify that f(f^-1(x))=x and f^-1(f(x))=x<br><br> f(x)= (x-1)/5

Lera25 [3.4K]

Find inverse function.
$f(x)= \frac{x-1}{5} 
\\y= \frac{x-1}{5} 
\\x= \frac{y-1}{5} 
\\y-1=5x
\\y=5x+1
\\f^{-1}(x)=5x+1
\\
\\f(x)= \frac{x-1}{5} 
\\f^{-1}(x)=5x+1 \\ \\f(f^{-1}(x))=f(5x+1)= \frac{(5x+1)-1}{5} = \frac{5x}{5}= x \\ \\ f^{-1}(f(x))=f^{-1}(\frac{x-1}{5} )=5\frac{x-1}{5}+1=x-1+1=x$

8 0

3 years ago