Answer:
see explanation
Step-by-step explanation:
Her error is in squaring (2y)²
She has (2y)² = 2y²
when it should be 2y × 2y = 4y²
Then
(2y)² = 6² + 8²
4y² = 36 + 64
4y² = 100 ( divide both sides by 4 )
y² = 25 ( take square root of both sides )
y = 
= 5
Answer:
D. (27x^6y^9) / x^9.
Step-by-step explanation:
(3x^2y^3 / z^3 )^3
= 3^3 x^(2*3)y(3*3) / z^(3^3)
= 27 x^6y^9 / x^9.
Answer:
B would equal -4
Step-by-step explanation:
<h3>
Answer: 2p + 3q</h3>
Work Shown:
log(200) = log(2^3*5^2)
log(200) = log(2^3) + log(5^2)
log(200) = 3*log(2) + 2*log(5)
log(200) = 3*q + 2*p
log(200) = 2p + 3q
The log rules I used were
log(A*B) = log(A)+log(B)
log(A^B) = B*log(A)
Answer:
y=5x-12
Step-by-step explanation:
The general equation of a line is <em>y=mx+b</em>.
The equation you currently have is <em>y=5x+b</em>.
Plug in the point (3,3) which will get you <em>3=5(3)+b</em>.
Solve the equation by solving what the y-intercept (b) is to create the new final equation.
3=5(3)+b
3=15+b
b=3-15
b=-12
y=5x-12
