Solve for x. 3x ^2 -4 = 8

Mathematics

2 answers:

LenKa [72]3 years ago

5 0

Answer:

x = ±2

Step-by-step explanation:

3x ^2 -4 = 8

Add 4 to each side

3x ^2 -4+4 = 8+4

3x^2 =12

Divide each side by 3

3x^2 =12

3x^2/3 = 12/3

x^2 = 4

Take the square root of each side

sqrt(x^2) = ±sqrt(4)

x = ±2

hodyreva [135]3 years ago

4 0

Answer:

x = 2

Step-by-step explanation:

3x ^2 -4 = 8

3x^2 = 12

3x^2/3 = 12/3

x^2 = 4

Square root 4 is 2

x = 2

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wlad13 [49]

Answer:

The possible pairs of sides are 90 and 120, 30 and 45, and 80 and 40.

Step-by-step explanation:

We know that 60 is a multiple of 15, 20, and 30, so we multiply by each factor to find all possible pairs: 10x6=60, 20x6=120, and 15x6=90, that gives your first pair, <u>90 and 120</u>.

We have now multiplied our first factor, 6. Now we need to multiply our second factor, 3: 20x3=60, 15x3=45, and 10x3=30. That gives your second pair, <u>30 and 45</u>.

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3 0

3 years ago

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Irina-Kira [14]

$x-\ adults\\
y-\ students\\\\ \left \{ {{5x+3.50y=2517.5} \atop {x+100=y}} \right.\\\\
5x+3.5(x+100)=2517.5\\\\
5x+3.5x+350=2517.5\ \ \ | subtract\ 350\\\\
8.5x= 2167,5\ \ \ | divide\ by\ 8.5\\\\
x=255\\\\
y=355\\\\
There\ were\ 355\ student\ tickets\ and\ 255\ adult\ tickets.$