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yuradex [85]
3 years ago
12

How many numbers are there between 1 and 1000 that dont include the digit 9

Mathematics
1 answer:
labwork [276]3 years ago
8 0
999 I think... let me know if that is correct:)
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Please help Q15!!!it will mean a lot +20 points
SashulF [63]

Answer:

c seems right

Step-by-step explanation:

4 0
3 years ago
Which graph represents f(x)=6cos(4πx) ?
lesya692 [45]

Answer:

The graph representing f(x)=6cos(4πx) is shown in the attached file.

Step-by-step explanation:

The graph representing f(x)=6cos(4πx) is shown in the attached file.

6 0
3 years ago
URGENT URGENT helppps plz
Murljashka [212]

Answer:

1) Bigger sector = 168.8pi

1) Smaller sector = 56.3pi

2) Bigger sector = 529.9

3) Smaller sector = 176.6

Step-by-step explanation:

1) Bigger sector =  \frac{270}{360}×pi×15×15

                          = 168.75pi

1) Smaller sector = \frac{360-270}{360}×pi×15×15

                             = \frac{90}{360}×pi×15×15

                             = 56.25pi

2) Bigger sector =  \frac{270}{360}×3.14×15×15

                           = 529.875

2) Smaller sector = \frac{360-270}{360}×3.14×15×15

                             = \frac{90}{360}×3.14×15×15

                             = 176.625

6 0
3 years ago
The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{236100}{8} = 29512.5

Sum of squares of differences = 3408750

S.D = \sqrt{\frac{3408750}{7}} = 697.82

Population mean, μ = $30,000

Sample mean, \bar{x} = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars} We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975

Now,

t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894

Since,                  

t_{stat} < t_{critical}

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

8 0
3 years ago
How many 0.2 liter glasses of water are contained in a 3.6 liter pitcher
PIT_PIT [208]
3.6 / 0.2 = 18 liter glasses :))
4 0
3 years ago
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