Answer:
if x=-1 then its is NOT in the domain of h.
Step-by-step explanation:
Domain is the set of values for which the function is defined.
we are given the function
h(x) = x + 1 / x^2 + 2x + 1
h(x) = x+1 /x^2+x+x+1
h(x) = x+1/x(x+1)+1(x+1)
h(x) = x+1/(x+1)(x+1)
h(x) = x+1/(x+1)^2
So, the function h(x) is defined when x ≠ -1
Its is not defined when x=-1
So, if x=-1 then its is NOT in the domain of h.
10r^3 ^ represents power of
Answer:
1
Step-by-step explanation:
y2 - y1/ x2 - x1
3-2/ 5-4 = 1/1 = 1
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