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puteri [66]
3 years ago
9

What is the domain of f(x) = -x2 + 4 g(x) = -3x

Mathematics
1 answer:
erica [24]3 years ago
6 0

Answer:

Step-by-step explanation:

(−∞,∞)

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True or false the values [x] and [-x] are always equal
RoseWind [281]

Answer:

If you mean |x| and |-x| yes they are equal.

Step-by-step explanation:

Brackets do not exactly specify the meaning of absolute value.

On most keyboards, above the enter button on the main keyboard part (not the keypad one) there is a back slash symbol \ and if you hold shift, there might be another symbol | which more accurately represents absolute value,

If you aren't talking about the absolute value, then no.

4 0
3 years ago
The slipe of the line passing through the points (7, 5) and (21, 15) is
SOVA2 [1]

Answer:

5/7

Step-by-step explanation:

You find a slope by using the equation y2-y1/x2-x1.

In this case: 15-5/21-7

10/14

5/7

6 0
3 years ago
There are 48 students in the 6th-grade band. If this represents 30% of the students in 6th grade, how many students are in the 6
Artemon [7]

Answer:

160

Step-by-step explanation:

had the question before

4 0
2 years ago
Read 2 more answers
Find the perimeter and simplify your answer
Lera25 [3.4K]

Answer:

32z-14

Step-by-step explanation:

2(9z-8)+2(7z+1)

18z-16+14z+2

simplify

32z-14

3 0
3 years ago
Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can ru
jenyasd209 [6]

Answer:

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time (t_{T}) that Keenan will be from home is the sum of run (t_{R}), hang out (t_{H}) and walk times (t_{W}), measured in hours:

t_{T} = t_{R}+t_{H}+t_{W}

If Keenan runs and walks at constant speed, then equation above can be expanded:

t_{T} = \frac{x_{R}}{v_{R}}+t_{H}+ \frac{x_{W}}{v_{W}}

Where:

x_{R}, x_{W} - Run and walk distances, measured in miles.

v_{R}, v_{W} - Run and walk speeds, measured in miles per hour.

Given that x_{R}=x_{W} = 2.5\,mi, v_{R} = 6\,\frac{mi}{h}, v_{W} = 4\,\frac{mi}{h} and t_{H} = 0.75\,h, the total time is:

t_{T} = \frac{2.5\,mi}{6\,\frac{mi}{h} } + 0.75\,h+\frac{2.5\,mi}{4\,\frac{mi}{h} }

t_{T} = 1.792\,h (1\,h\,48\,m)

Kennan will be from home approximately an hour and 48 minutes.

7 0
3 years ago
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