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3 years ago

Please help!! I need to know this by today

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

3 0

Your answer would be 6cm by 48cm because if your ratio is 1:8 your second number would be eight times the cm of your first number. 6*8=48

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5+68empty space, 5, plus, 68 =(3+=(3+equals, left parenthesis, 3, plus 5 )+ 68)+68right parenthesis, plus, 68 =3 + (=3+(equals,

hoa [83]

Answer:

Give me and example

Step-by-step explanation:

6 0

3 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

Read 2 more answers

Karley is an architect building the city pool. The larger rectangle represents the entire pool area. The smaller rectangle repre

Ahat [919]

Answer:

Area of the walkway border is 736 ft²

Step-by-step explanation:

A rectangle is a quadrilateral (has four sides and four angles) with two pairs of opposite and parallel sides. All angles in a rectangle are 90 degrees each. Also, opposite sides are equal.

The entire pool area has a length of 60 feet and width of 40 feet. The area of the entire pool area is:

Area of entire pool = length * width = 60 feet * 40 feet = 2400 ft²

The area of entire pool

A walkaway border of 4 ft is made around the pool area. There is a decrease of 4 ft round the sides of the pool area.

Therefore length of pool = length of entire pool area - 4 feet border at left - 4 feet border at right = 60 ft - 4 ft - 4 ft = 52 ft

width of pool = width of entire pool area - 4 feet border at top - 4 feet border at bottom = 40 ft - 4 ft - 4 ft = 32 ft

Therefore the pool is 52 ft × 32 ft

Area of pool = length * width = 52 ft * 32 ft = 1664 ft²

Area of the walkway border = Entire pool area - Area of pool = 2400 ft² - 1664 ft² = 736 ft²

8 0

2 years ago

Find the area of the shaded region.<br>pls do this with explanation.<br>

vladimir1956 [14]

Answer:

first find the area of the big rectangle = 12×14=168

area of the small unshaded rectangle =2×5×6=60

area of the shaded region = 168-60=108

6 0

2 years ago

Read 2 more answers

Use the substitution method

vitfil [10]

Answer:

z = 9

z = 2

z = 5

z = 8

z = 11

Step-by-step explanation:

5 0

2 years ago