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Komok [63]
3 years ago
15

Simplify a^5 take away a^3

Mathematics
1 answer:
sineoko [7]3 years ago
3 0

Answer:

Step-by-step explanation:

If it was like....\frac{a^{5}}{a^{3}}

then you subtract 5 minus 3 to be left with a^2 on the numerator

That would be how you would take it away.

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Can u please help me I don't understand and it's do tomorrow please
Andrej [43]

What’s due for tomorrow?

7 0
3 years ago
What is 4 minus 1 5/12
klasskru [66]

Answer: 2 and 7/12

Step-by-step explanation: To subtract 4 - 1 and 5/12, first subtract the fractions. Since 4 has no fraction, imagine the fraction 0/12.

Notice however that we can't subtract 0/12 - 5/12.

So, let's rewrite 4 and 0/12 as 3 + 1 and 0/12 or 3 + 12/12 by changing 1 and 0/12 into an improper fraction.

Now we have 3 and 12/12 - 1 and 5/12.

Now we can subtract our fractions 12/12 - 5/12 and we get 7/12. Next we subtract our whole numbers 4 - 1 to get 3.

So 5 - 1 and 5/12 is 2 and 7/12.

4 0
4 years ago
Read 2 more answers
Solve the inequality and enter your solution as an inequality comparing the
sammy [17]

Answer:x>1

Step-by-step explanation:

Subract 11 from both sides

8 0
2 years ago
Slove and answer -2(x+3y)=18
Brums [2.3K]

Answer:

Let's solve for x.

−2(x+3y)=18

Step 1: Add 6y to both sides.

−2x−6y+6y=18+6y

−2x=6y+18

Step 2: Divide both sides by -2.

−2x/−2

=

6y+18

−2

x=−3y−9

Answer:

−3y−9

8 0
3 years ago
Read 2 more answers
Determine whether each function has a maximum or minimum value. Then find the value
Nataliya [291]
For f(x)=ax²+bx+c
if a is positive, then it is concave up and the verx is minimum
if a is ngative then it is concave down and vertex is maximum

hack: in form f(x)=ax²+bx+c, the x value of vertex is -b/2a
to find y value, just subsitutte that value for x in f(x)

so
y=-1x²+4x-4
negative, so vertx is max
x value of vertex is -4/(2*-1)=-4/-2=2
find f(2) or subsitute 2 for x
y=-1(2)²+4(2)-4
y=-1(4)+8-4
y=-4+4
y=0

maximum is 0

A is answer
8 0
3 years ago
Read 2 more answers
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