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julsineya [31]
3 years ago
11

How to plug into the table the y-coordinate​

Mathematics
1 answer:
barxatty [35]3 years ago
6 0

Step-by-step explanation:

the y coordinate is always the second value. for example, if u have (3,2) the y value is 2

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A wedding reception is held at a restaurant in Mississippi. The food and drinks cost $1492.50. The state sales tax rate is 7%, a
zhannawk [14.2K]
Part A: multiply 7%*1492.50 = $104.475
Part B: multiply 20%*1492.5= $298.5
Part C: add 1492.5+104.475+298.5 = $1895.475
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C is the set of months whose name consists of 6 letters choose the correct answer
Archy [21]

Answer:

August

Step-by-step explanation:

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3 years ago
Marco made of rectangular prism using 1/2 m cubes the rectangular prism has a volume of 5 m³ how many cubes did Marco use
Nookie1986 [14]
Ok so
1 find volume of 1 cube
2. find total volume of rectangular prism

1/2 m cubes
volume=side^3
side=1/2m (I guess since that was what was given)
v=1/2^3=1/8

so
volume of 1 cube times number of cubes=total volume
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needs 40 cubes
8 0
3 years ago
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

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