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mart [117]
3 years ago
13

Sam made a square sign with an area of 410 square inches.What is the approximate perimeter of the square sign?

Mathematics
2 answers:
Leviafan [203]3 years ago
6 0
Each side of the square = square root of 410  = 20.248 inches

so the perimeter = 4 * 20.248  =  81.7 inches to nearest tenth of an inch
Masteriza [31]3 years ago
4 0
Are you takeing the exam to.
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Find the different between compound interest payable anually and half anually for a amount Rs14000 at the rate of 12•\•per annum
Ostrovityanka [42]

Answer:

$113.08

Step-by-step explanation:

The formula for calculating future value:

FV = P (1 + r/m)^mn

FV = Future value  

P = Present value  

R = interest rate  

N = number of years

m = number of compounding

14,000(1.12)^2 =  17,561.60

14,000 ( 1 + 0.12/2)^(2x2) = 17674.68

Difference :  17674.68 -   17,561.60 = $113.08

8 0
2 years ago
What is the vertical asymptote for this function?<br> y=1/x-2
nataly862011 [7]

Answer: x = 0

Step-by-step explanation: so x = 0 is the equation of the vertical asymptote, and 0 must be left out of the domain: (−∞,0)U(0,∞) in interval notation.

8 0
3 years ago
(24x3 − 14x2 + 20x + 6) ÷ (4x2 − 3x + 5) = Q + <br> R<br> 4x2 − 3x + 5
riadik2000 [5.3K]

Answer:

Q= 6x+1

R= -7x+1

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please please please help me with this...
dlinn [17]

Answer:

It's option d.

Step-by-step explanation:

The line y = x + 2 has domain x < 2 (because of the clear circle.)

The lines y = x + 1 has domain x ≥ 2. ( because of the filled circle).

7 0
3 years ago
Solve<br><img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D
Nostrana [21]

Answer:

\displaystyle   \begin{cases} \displaystyle  {x} _{1} =  - p \\   \displaystyle x _{2}   =  -  q \end{cases}

Step-by-step explanation:

we would like to solve the following equation for x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}  +  \frac{1}{x}  =  \frac{1}{p  + q + x}

to do so isolate \frac{1}{x} to right hand side and change its sign which yields:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{1}{p  + q + x}  -  \frac{1}{x}

simplify Substraction:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{x - (q + p +  x)}{x(p  + q + x)}

get rid of only x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{  - (q + p )}{x(p  + q + x)}

simplify addition of the left hand side:

\displaystyle  \frac{q + p}{pq}     =  \frac{  - (q + p )}{x(p  + q + x)}

divide both sides by q+p Which yields:

\displaystyle  \frac{1}{pq}     =  \frac{  -1}{x(p  + q + x)}

cross multiplication:

\displaystyle    x(p  + q + x)  =   - pq

distribute:

\displaystyle    xp  + xq +  {x}^{2} =   - pq

isolate -pq to the left hand side and change its sign:

\displaystyle    xp  + xq +  {x}^{2} + pq =  0

rearrange it to standard form:

\displaystyle   {x}^{2} +    xp  + xq  + pq =  0

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so

factor out x:

\displaystyle  x( {x}^{} +   p ) + xq  + pq =  0

factor out q:

\displaystyle  x( {x}^{} +   p ) +q (x + p)=  0

group:

\displaystyle  ( {x}^{} +   p ) (x + q)=  0

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

\displaystyle   \begin{cases} \displaystyle  {x}^{} +   p  = 0 \\   \displaystyle x + q=  0 \end{cases}

cancel out p from the first equation and q from the second equation which yields:

\displaystyle   \begin{cases} \displaystyle  {x}^{}   =  - p \\   \displaystyle x  =  -  q \end{cases}

and we are done!

3 0
3 years ago
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