RX is + XS is the hypotenuse of the right triangle RTS, then:
(RX + XS)^2 = (RT)^2 + (ST)^2
=> (4+9)^2 = (RT)^2 + (ST)^2
=> 13^2 = (RT)^2 + (ST)^2 .....equation (1)
Triangle RTX and XST are also right triangles.
RT is the hypotenuse of RTX and ST is the hypotenuse os SXT.
Then, (RT)^2 - (RX)2 = (TX)^2 and (ST)^2 - (SX)^2 = (TX)^2
=> (RT)^2 - (RX)^2 = (ST)^2 - (SX)^2
=> (RT)^2 - (ST)^2 = (RX)^2 -(SX)^2
=> (RT)^2 - (ST)^2 = 4^2 - 9^2 = 16 - 81 = - 65
=> (ST)^2 - (RT)^2 = 65 ..........equation (2)
Now use equations (1) and (2)
13^2 = (RT)^2 + (ST)^2
65 = (ST)^2 - (RT)^2
Add the two equations:
13^2 + 65 = 2(ST)^2
2(ST)^2 =178
(ST)^2 = 234/2 = 117
Now use (ST)^2 - (SX)^2 = (TX)^2
=> (TX)^2 = 117 - 81 = 36
=> (TX) = √36 = 6
Answer: 6
Answer:
1 = 52°
2=79°
3= 38°
Step-by-step explanation:
each triangle equals 180°
and 1 and 3 also make a right angle which should always be 90°
40,000 children
8% has allergies
The rest do not have allergies or 100%-8%
So, 92% do not have allergies.
Who do not have allergies
.92*40,000 = 36,800 children
Answer:
x= -1
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
0.8
Step-by-step explanation:
The question here says that In a class of 30 students, 18 are men, 6 are earning a B, and no men are earning a B. If a student is randomly selected from the class, find the probability that the student is a man or earning a B.
Since the question says that 18 out of 30 students are men,6 out of the remaining people earn a "B" and non of the 18 men earn a "B".
The probability of picking a man or a person that earns a "B" is
18/30 (since there are 18 men out of the 30 students)
And 6/30(since there are 6 people that earn a "b")
The probability of picking a man or a "b" earner is
18/30 + 6/30
= 24/30 or 0.8