Part A: 0.7(x)
Part B: 8.96/0.7 ---> (You can solve this by yourself)
For getting the answer, you can assume the regular price of the book is x. Then, the sale price would be x-0.3x, which is 0.7x
For part B, the price is 0.7 of the original. Dividing the number by 0.7 gets you the original price
Answer:
ew423q4rw32432ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph -2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2erw3r5432
Step-by-step explanation:
дешовок овц в гавне собак гандонов xddddddddddddddddddddddddddddddd
You would have to divide 16.50 into 3 then put your answer down hope this helps