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marysya [2.9K]
3 years ago
12

How to graph f(x)=2x^2-2

Mathematics
1 answer:
MariettaO [177]3 years ago
6 0

Answer:

ew423q4rw32432ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph -2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2erw3r5432

Step-by-step explanation:

дешовок овц в гавне собак гандонов xddddddddddddddddddddddddddddddd

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Which expression is equivalent to StartRoot 128 x Superscript 8 Baseline y cubed z Superscript 9 Baseline EndRoot? Assume y grea
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Answer:

Option C.

Step-by-step explanation:

The given expression is  

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It can be written as

\sqrt{(64\cdot 2)\cdot x^8\cdot y^{2+1}\cdot z^{8+1}}

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The Figure is made up of 2 rectangels and 2 right triangel's What is the area of the figure?
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OlgaM077 [116]

Answer:

28

Step-by-step explanation:

We know that the heights and bases of all of the parallelograms will be the same because they are equal, therefore, since the height of 2 parallelograms is 14, the height of one parallelogram is 14 / 2 = 7. Since the areas of all of the parallelograms are congruent, the area of one parallelogram is 308 / 4 = 77. The parallelogram area formula is A = bh where A, b and h are area, base and height respectively and we know both the area and height so we need to solve for b. Doing so we get 77 = b * 7 so that means b = 11. The length of y is two bases + 6 and since we know the base is 11, y = 11 * 2 + 6 = 22 + 6 = 28.

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