Question

PLEASE HELP THIS IS DUE TODAY (10 POINTS)

Answer 1

lets see there are 16 possible outcomes below

HHHH HTHH THHH TTHH

HHHT HTHT THHT TTHT

HHTH HTTH THTH TTTH

I think #1 should be HHHH HTHH

HHHT HTHT

HHTH HTTH

HHTT HTTT

But its been awhile just trying to help out

Answer 2

Remark

There are 16 results of throwing a coin 4 times.

Answer 4 first.

These are independent events. No matter what the first result or the second or the third result is outcome can only be 1/2 for any given throw. One event does not influence any other.

One

What this means is that it does not matter what else might be true as long as the second event is heads. So you count THTT and HHHH as both being true. If you use your table, I believe there are 8 results where heads is in the second position.

Two

The last position will also contain heats 8 times. Just count them up. Some of them will be duplicated from your first answer. It does not matter. For example, HHHH will appear in both lists.

Three

For Heads in the second AND the last position you should get 4. They are HHHH THHH THTH HHTH

Answers

P(one) = 8/16. You get 8 answers out of 16 to get a heads in position 2.

P(Two) = 8/16. You get 8 answers out of 16 to get a heads in position 4

P(Three) = 4/16. You get 4 answers out of 16 to get a heads in positions 2 and 4