The length of the line segment connecting (4,1) and (7,-5) is

Step 6: Patterns can provide a clear understanding of mathematical relationships. This can be seen very clearly in the form of m

kenny6666 [7]

Two more examples of relationship patterns found in mathematics are <u>Geometric sequences</u><u> and </u><u>Fibonacci numbers</u>.

<h3>What are mathematical patterns?</h3>

Mathematical patterns are a sequence of repeated arrangements of numbers, shapes, colors, letters, etc.

Mathematical patterns are usually abstract.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence of non-zero numbers. The first number is the product of multiplying a previous number by a fixed, non-zero number, called the common ratio.

A Geometric sequence may look like: 2, 4, 8, 16, 32, 64, 128, ..., where the common ratio is 2.

<h3>What is a Fibonacci sequence?</h3>

A Fibonacci number starts with a zero, followed by a one, then by another one, and then by a series of steadily increasing numbers.

The rule of the Fibonacci sequence is that each number is equal to the sum of the preceding two numbers, for example, 0, 1, 1, 2, 3, 5, 8, 13.

Learn more about mathematical patterns at brainly.com/question/854376

#SPJ1

5 0

2 years ago

The lifetime of LCD TV sets follows an exponential distribution with a mean of 100,000 hours. Compute the probability a televisi

kondaur [170]

Answer:

0.9

0.3012

0.1809

230258.5

Step-by-step explanation:

Given that:

μ = 100,000

λ = 1/μ = 1 / 100000 = 0.00001

a. Fails in less than 10,000 hours.

P(X < 10,000) = 1 - e^-λx

x = 10,000

P(X < 10,000) = 1 - e^-(0.00001 * 10000)

= 1 - e^-0.1

= 1 - 0.1

= 0.9

b. Lasts more than 120,000 hours.

X more than 120000

P(X > 120,000) = e^-λx

P(X > 120,000) = e^-(0.00001 * 120000)

P(X > 120,000) = e^-1.2

= 0.3011942 = 0.3012

c. Fails between 60,000 and 100,000 hours of use.

P(X < 60000) = 1 - e^-λx

x = 60000

P(X < 60,000) = 1 - e^-(0.00001 * 60000)

= 1 - e-^-0.6

= 1 - 0.5488116

= 0.4511883

P(X < 100000) = 1 - e^-λx

x = 100000

P(X < 60,000) = 1 - e^-(0.00001 * 100000)

= 1 - e^-1

= 1 - 0.3678794

= 0.6321205

Hence,

0.6321205 - 0.4511883 = 0.1809322

d. Find the 90th percentile. So 10 percent of the TV sets last more than what length of time?

P(x > x) = 10% = 0.1

P(x > x) = e^-λx

0.1 = e^-0.00001 * x

Take the In

−2.302585 = - 0.00001x

2.302585 / 0.00001

= 230258.5

3 0

3 years ago

The first two terms of an arithmetic sequences are 7 and 3.

Katyanochek1 [597]

Answer:

1.1.1) -61

1.1.2) Term 42

Step-by-step explanation:

Tn= dn (difference) + t0 (term 0)

Tn= -4n+ 11

You can now take this general rule to find out the other terms.

Tn= -4(18)+11

Tn= -61

And the term -157

Tn= -4n+11

-157= -4n + 11

-157 - 11= - 4n

-168= -4n

-168/-4= n

42= n

3 0

3 years ago

A certain forest covers an area of 4300 km2 . suppose that each year this area decreases by 3.25% . what will the area be after

Gemiola [76]

A =P(1-3.25%)⁸

A= 3,301.23 km²

7 0

3 years ago

What is the value of a N?

spin [16.1K]

You answer should be 8 and 11 maybe I don't know

8 0

3 years ago

Read 2 more answers