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Dimas [21]
4 years ago
12

Find the lim a to b idk hiw to do it

Mathematics
1 answer:
Elina [12.6K]4 years ago
5 0
\bf \lim\limits_{a\to b} \cfrac{a^2-3ab+2b^2}{a-b}\implies \lim\limits_{a\to b} \cfrac{(a-1b)(a-2b)}{a-b}
\\\\\\
\lim\limits_{a\to b} \cfrac{\underline{(a-b)}(a-2b)}{\underline{a-b}}
\implies 
\lim\limits_{a\to b} a-2b\implies \lim\limits_{a\to b} b-2b\implies \lim\limits_{a\to b}-b
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The sum of three consecutive integers is 21 larger than twice the smallest integer. find the integers.
Darya [45]
Let the integers be x-1, x, x+1.

Given,

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4 years ago
(4x^(4))^(2) without exponents
vlabodo [156]

Answer:

256x * 16

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3 years ago
I'm not sure how to solve for x
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4 years ago
The polar coordinates of a point are 3π 4 and 7.00 m. What are its Cartesian coordinates (in m)? (x, y) = 6.06,−3.5 m
Keith_Richards [23]

Answer:

a) \left(x,y\right)=\left(4.95,-4.95\right)

b) r\angle\theta = 7\angle0.5236\,\text{radians}

Step-by-step explanation:

Polar coordinates are represented as: r\angle\theta, where 'r' is the length (or magnitude) of the line, and '\theta' is the angle measured from the positive x-axis.

in our case:

7\angle\dfrac{3\pi}{4}

to covert the polar to cartesian:

x = r\cos{\theta}

y = r\sin{\theta}

we can plug in our values:

x = 7\cos{\dfrac{3\pi}{4}} = -7\dfrac{\sqrt{2}}{2}

y = 7\sin{\dfrac{3\pi}{4}} = 7\dfrac{\sqrt{2}}{2}

the Cartesian coordinates are:

\left(x,y\right)=\left(-7\dfrac{\sqrt{2}}{2},7\dfrac{\sqrt{2}}{2}\right)

\left(x,y\right)=\left(4.95,-4.95\right)

(b) to convert (x,y) = (6.06,-3.5)

we'll use the pythagoras theorem to find 'r'

r^2 = x^2+y^2

r^2 = (6.06)^2+(-3.5)^2

r = \sqrt{48.97} \approx 7

the angle can be found by:

\tan{\theta} = \dfrac{y}{x}

\tan{\theta} = \dfrac{3.5}{6.06}

\theta = \arctan{left(\dfrac{3.5}{6.06}\right)}

\theta = 0.5236 \text{radians}

to convert radians to degrees:

\theta = 0.5236 \times \dfrac{180}{\pi} \approx 30^\circ

writing in polar coordinates:

r\angle\theta = 7\angle30^\circ\,\,\text{OR}\,\,7\angle0.5236\,\text{radians}

5 0
3 years ago
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