Answer:
7x^2 −12x−10
Step-by-step explanation:
((5x2 - 8x) + 1) + (2x2 - 4x - 11)
Factoring 7x2-12x-10
The first term is, 7x2 its coefficient is 7 .
The middle term is, -12x its coefficient is -12 .
The last term, "the constant", is -10
Step-1 : Multiply the coefficient of the first term by the constant 7 • -10 = -70
Step-2 : Find two factors of -70 whose sum equals the coefficient of the middle term, which is -12 .
-70 + 1 = -69
-35 + 2 = -33
-14 + 5 = -9
-10 + 7 = -3
-7 + 10 = 3
-5 + 14 = 9
-2 + 35 = 33
-1 + 70 = 69
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
hello :
<span>14ax-y+2ay-7x = (14ax+2ay) +(-y -7x) = 2a(7x+y) - (7x+y)
</span>14ax-y+2ay-7x = (7x+y)(2a - 1)
Answer:
C)
Step-by-step explanation:
got it right on edge :)
Step-by-step explanation:
angle YWX = angle YXW ...eqn 1
angle XYZ = angle WYX (0.5) = 15x...eqn 2
angle YXZ = angle YXW = 2x + 5...eqn 3
=> from eqn 1 and 3 we get...
angle YWX = 2x + 5 ...eqn 4
=> from eqn 2 we get
angle WYX = 2 × angle XYZ = 30x...eqn 5
a triangle has a total of 180deg,
=>angle WYX + angle YWX + angle YXW = 180deg
=> 30x + 2x +5 + 2x +5 = 180deg
=> 34x +10 =180deg
=> x = 5deg
subst x = 5deg in eqn 5, we get
angle WYX = 30 × 5 = 150deg
Answer:
S8 = 112
Step-by-step explanation:.
The question is incomplete
Assuming we are given the following
First term a =7
number of terms n = 8.
Common difference d=2
We can find the sum of the first 8terms S8
Substitute the given values
S8 = 8/2[2(7)+(8-1)(2)]
S8 =4(14+7(2))
S8=4(14+14)
S8 = 4(28)
S8 = 112
Hence the sum of the first 8terms is 112
Note that the values are assumed values
