All categories

3 years ago

Solve for x, worth 10 points

Mathematics

1 answer:

Anton [14]3 years ago

8 0

Answer: x=22

Step-by-step explanation:

Since the angles are corresponding angles, use x+14=5x-74. You get 36=36 meaning it is right when you substitute the value for x.

x+14=5x-74

-x on both sides

14=4x-74

+74 on both sides

88=4x

Divide both sides by 4

x=22

You might be interested in

Write the standard form of the line that contains a slope of -3/2

Firdavs [7]

Answer:

3x + 2y = 12

Step-by-step explanation:

The standard form is expressed as Ax + By = C

5 0

2 years ago

Two investments totaling $21,000 produce an annual income of $870. One investment yields 4% per year, while the other yields 10%

Citrus2011 [14]

Answer:

The amount invested at 4% is $20,500 and the amount invested at 10% is $500

Step-by-step explanation:

Let

x -----> the amount invested at 4%

(21,000 -x) ----> the amount invested at 10%

we know that

The interest of the amount invested at 4% plus the interest of the amount invested at 10% must be equal to $870

$4\%=4/100=0.04$

$10\%=10/100=0.10$

$0.04(x)+0.10(21,000-x)=870$

Solve for x

$0.04x+2,100-0.10x=870$

$0.10x-0.04x=2,100-870$

$0.06x=1,230$

$x=\$20,500$

$21,000-x=\$500$

therefore

The amount invested at 4% is $20,500 and the amount invested at 10% is $500

7 0

3 years ago

-2w^2+201.02=66.54<br> Round to the nearest hundredth

bulgar [2K]

-2w^2=66.54-201.02
-2w^2= -134.48
w^2 = 134.48/2
w=square root of (67.24)=8.20

7 0

3 years ago

I picked the yellow one, was I correct?

Black_prince [1.1K]

Answer:

yes

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago