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igomit [66]
3 years ago
13

Given the number 2,357,841, in what place value is the 5?

Mathematics
2 answers:
mylen [45]3 years ago
8 0
It is in the ten thousands place
nalin [4]3 years ago
6 0
Ten thousands. Hope this help!
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I need help, please<br> it is do tomorrow
Morgarella [4.7K]

Answer:

8) 21 milliliters

i am not completly sure but it is NOT the whole

9) .4 & 40%

7) 9670 feet

10) a) $7200       b)350,000

Step-by-step explanation:

cuz 35% of 60 is 21

cuz 120/300 is .4 and if you take 300 * .4 it equals 120

7 0
3 years ago
Conversion. Write a reduced fraction notation for 0.56.
____ [38]

Answer:

Reduced fraction: 14/25

Step-by-step explanation:

To write 0.56 in terms of fractions we need to multiply and divide the number by 100:

(0.56 * 100)/100 = 56/100. Then we simplify the fraction by dividing the numerator and denominator by the common factor 2 as many times as possible:

56/100 = 28/50 = 14/25

The fraction 14/25 cannot be more simplified

7 0
3 years ago
Read 2 more answers
The equation y=7.6x represents a proportional relationship what is the constant of proportionality?
prisoha [69]

Answer:

Option B. 7.6

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

where

k is the constant of proportionality

The slope of the linear equation is the same that the constant of proportionality

In this problem we have

y=7.6x

so

the slope is m=7.6

therefore

The constant of proportionality k is k=7.6

5 0
3 years ago
Let X1, X2 and X3 be three independent random variables that are uniformly distributed between 50 and 100.
sergejj [24]

Answer:

a) the probability that the minimum of the three is between 75 and 90 is 0.00072

b) the probability that the second smallest of the three is between 75 and 90 is 0.396

Step-by-step explanation:

Given that;

fx(x) = { 1/5 ; 50 < x < 100

              0, otherwise}

Fx(x) = { x-50 / 50 ; 50 < x < 100

                          1 ;   x > 100

a)

n = 3

F(1) (x) = nf(x) ( 1-F(x)^n-1

= 3 × 1/50 ( 1 - ((x-50)/50)²

= 3/50 (( 100 - x)/50)²

=3/50³ ( 100 - x)²

Therefore P ( 75 < (x) < 90) =  ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx

= 3/50³ [ -2 (100 - x ]₇₅⁹⁰

= (3 ( -20 + 50)) / 50₃

= 9 / 12500 = 0.00072

b)

f(k) (x) = nf(x)  ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k

Now for n = 3, k = 2

f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))

= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)

= 6/50³ ( 150x - x² - 5000 )

therefore

P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx

= 99 / 250 = 0.396

3 0
2 years ago
The Perimeter is x+38
OLga [1]
P=x+38

add all individual sides together (is also the perimeter):
p=(x+3)+(x-5)+x+(x-2)+(x-4)+(x-1)+(x-1)
=7x-10

set both p equal:
x+38=7x-10
38=6x-10
48=6x
8=x

then insert x=8 in all the side/perimeter equations:
p=x+38=8+38=46

sides:
x=8
x-2=8-2=6
x-1=8-1=7
x-4=8-4=4
x-5=8-5=3
x+3=8+3=11
8 0
3 years ago
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