6.4 is the answer hope this helps
Answer:
(3,-1/2)
Step-by-step explanation:
Midpoint formula
for
(x1,y1) and (x2,y2)
the point is
((x1+x2)/2,(y1+y2)/2)
(8,2)
(6,10)
point is
((8+6)/2,(2+10)/2)
(14/2,12/2)
(7,6)
midpoint is (7,6)
Answer: In the resulting equation: " a² - 12a + 32 = 0 " ;
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The "coefficient" of the "a" term is: " - 12" .
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The "constant" is: " 32 " .
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Explanation:
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Let: "a = x² + 4 " .
Given: (x² + 4)² + 32 = 12x² + 48 ;
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Factor: "12x² + 48" into " (x² + 4) " ;
"12x² + 48" = 12 (x² + 4) " ;
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Given: (x² + 4)² + 32 = 12x² + 48 ;
rewrite as; "a² + 32 = 12a " ;
Subtract "12a" from each side of the equation;
"a² + 32 - 12a = 12a - 12a ;
to get:
" a² - 12a + 32 = 0 " .
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The coefficient of the "a" term; that is:
The "coefficient" of " -12a" ; is: "- 12" .
The constant is: "32<span>" .
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