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Mumz [18]
3 years ago
8

ALGEBRA QUESTION WILL GIVE BRAINLIEST IF CORRECT!!!

Mathematics
1 answer:
Ulleksa [173]3 years ago
3 0

Answer:

Step-by-step explanation:

(f + g)(x) simply means that you are adding together the 2 functions that are written in terms of x.

x^3-x+x^3+2x^2-10

The only like terms we have there are the x-cubed's, so

2x^3+2x^2-x-10=(f+g)(x)

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Which expression is equivalent to
zmey [24]
The answer is B because reread the question
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2 years ago
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HELP!! What is the approximate measure of angle x in the triangle shown?
Alex Ar [27]
<h3>Answer:   D)  130.5 degrees</h3>

=================================================

Work Shown:

c^2 = a^2 + b^2 - 2*a*b*\cos(C)\\\\10^2 = 5^2 + 6^2 - 2*5*6*\cos(x)\\\\100 = 25 + 36 - 60*\cos(x)\\\\100 = 61 - 60*\cos(x)\\\\100 - 61 = - 60*\cos(x)\\\\39 = - 60*\cos(x)\\\\\cos(x) = \frac{39}{-60}\\\\\cos(x) = -0.65\\\\x = \arccos(-0.65)\\\\x \approx 130.5416\\\\x \approx 130.5\\\\

Note: I used the law of cosines. Make sure your calculator is in degree mode.

6 0
3 years ago
Dr. Tu must administer emergency medicine to his patient, Mrs. Jones. The
galben [10]

Answer:

168

Step-by-step explanation: You would do 140/100 = 1.4 then multiply 120 by 1.4 which is 168.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
2 years ago
Which of the following is the product of the rational expressions shown below?
Veseljchak [2.6K]

Answer:

the answers D.

6 0
3 years ago
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