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Trava [24]
3 years ago
13

What is the meaning of this WW1 quote?

Mathematics
1 answer:
Ghella [55]3 years ago
3 0
The Great War (WW1) killed many empires who had been around for hundreds of years. It introduced some very inhumane weapons such as gas, and was the 1st war when old tactics met new ones. Back then, a war on this scale has never been seen. 

It also gave birth to many new nations 
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Solve for x and y<br>2x+3yi=-14+9i
ryzh [129]
2,314 is the anwser

4 0
3 years ago
How do I get this answer?
Keith_Richards [23]

Answer:

Step-by-step explanation:

Several trig identities are involved in the proof of this. This is the order in which they are used.

  • cos(2x) = cos²(x) -sin²(x)
  • cos²(x) +sin²(x) = 1
  • cos(x) = 1/sec(x)

<h3>Proof</h3>

Starting with the left side, we can transform it into the right side.

  2\cos(2x)=2(\cos^2(x)-\sin^2(x)) = 2(\cos^2(x)-(1-\cos^2(x)))\\\\=2(2\cos^2(x)-1)=2\left(\dfrac{2}{\sec^2(x)}-\dfrac{\sec^2(x)}{\sec^2(x)}\right)\\\\=\boxed{\dfrac{4-2\sec^2(x)}{\sec^2(x)}}

4 0
2 years ago
Line I is parallel to line m.if the maesure of angle 6 is 75 what is the measure of angle 3
devlian [24]

Answer:

105

Step-by-step explanation:

l is parallel m so angle 3+angle 6=180

8 0
3 years ago
At 3:00 the temperature in Alaska began dropping at a constant rate. The equation y = –5x – 10 can be used to represent this sit
alina1380 [7]

Answer:

C

Step-by-step explanation:

Hope this helps <3

Stay safe!

Get good grades :)

Stay awsome              

                                        ~ Coco

6 0
3 years ago
What is the solution set of x2 + 5x + 1 = 0?
DerKrebs [107]

Answer:

\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}

Step-by-step explanation:

x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}

\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}

3 0
3 years ago
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