One particular 33 feet tall cone dry sand has a base diameter of 97.8 feet. To the nearest tenth of a degree, what is the angle

Question

4 years ago

9

of repose of this type of dry sand?

2 answers:

Dennis_Churaev [7] · Answer 1 · 2022-02-16T23:32:25+03:00

Answer:

Angle of repose of the cone of dry stand is 34.1°

Step-by-step explanation:

Angle of repose of a cone shaped mountain is the angle between base of the mountain and height as shown in the figure attached.

From the triangle ABC,

tanB = $\frac{AD}{BD}$

= $\frac{AD}{\frac{BC}{2}}$

= $\frac{33}{\frac{97.5}{2} }$

= $\frac{66}{97.5}$

tanB = 0.6769

B = $tan^{-1}(0.6769)$

= 34.09°≈ 34.1°

Therefore, angle of repose of the cone of dry stand is 34.1°

Gemiola [76] · Answer 2 · 2022-02-16T21:50:12+03:00

5 0

Answer:

This forms a right triangle with height = 33 and side = 48.9

arc tan (angle) = 33/48.9

arc tan (angle) = 0.6748466258

angle = 34.0 Degrees

Step-by-step explanation: