Answer:
each of the pairs of opposite angles made by two intersecting lines.Step-by-step explanation:
<u>If you're wanting it alone just with the exponents, here is how you're going to do it:</u>
Technically, the 2 alone has a power, and it's simply just one. When exponents are being used in numbers multiplying together, they add.
So, to simplify this it'd be 2^5.
<u>If you're wanting the actual answer, you would do exponents first. Remember that exponents are just the number being multiplied by itself x times:</u>
2 x 2 x 2 x 2 = 16
Now we just need to multiply this by 2 and you'll get 32.
OR, if you do the 2^5, you'll still get 32!
Answer:
sorry wish i knew to need the answer also
Step-by-step explanation:
Answer:
0.9451
Step-by-step explanation:
Remaining question? <em>"How is the result affected by the additional information that the survey subjects volunteered torespond?"</em>
Probability that at least 1 user is more careful about personal information when using a public Wi-Fi hot spot is:
P(X≥1) = 1 − P(X<1)
= 1 − P(X=0)
= 1 - [(3,0) (0.62)^0 (1-0.62)^3-0
= 1 - 0.054872
= 0.945128
= 0.9451
Thus, the probability that among three randomly selected Internet users; at least one is more careful about personal information when using a public Wi-Fi hotspot is 0.9451
Taking

and differentiating both sides with respect to

yields
![\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B3x%5E2%2By%5E2%5Cbigg%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B7%5Cbigg%5D%5Cimplies%206x%2B2y%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%3D0)
Solving for the first derivative, we have

Differentiating again gives
![\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B6x%2B2y%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B0%5Cbigg%5D%5Cimplies%206%2B2%5Cleft%28%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%5Cright%29%5E2%2B2y%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dx%5E2%7D%3D0)
Solving for the second derivative, we have

Now, when

and

, we have