Use the substitution method to solve the system of equations. Please help me get this question right
1 answer:
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SA= Lateral Area + Area (of base)
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm
<h2>Evaluating Composite Functions</h2><h3>Answer:</h3>
We can write how will be defined but that's too much work and it's only useful when we are evaluating
with many inputs.
First let's solve for first. As you read through this answer, you'll get the idea of what I'm doing.
Given:
Solving for :
Now we can solve for , since
,
.
Given:
Solving for :
Now we are can solve for . By now you should get the idea why
.
Given:
Solving for :