Answer:
the answer is A {-5,-3,-1}
Answer:
B. Solve each equation for a variable
Is (-1,13) a solution of the system: Yes it is x =1, y= 13
Step-by-step explanation:
-4x=30-2y
- 15 = - 2y + 11x
-4x=30-2y
-2y+4y = -30-------------------i
- 2y + 11x= - 15 ---------------ii
make x the subject of formula in equ i
-4x=30-2y
x= (30-2y)/-4
insert x= (30-2y)/-4 in equ ii
- 2y + 11x= - 15
-2y+ 11((30-2y)/-4)= -15
-2y+(330-22y)/4 = -15
-8y+330-22y/4 = -15
-8y-22y+330/4= -15
cross multiply
-30y+330 = 4x-15 = -60
-30y = -60-330
-30y =--390
y= -390/-30 = 13
if y = 13
x = (30-2y)/-4 = (30-2x13)/-4 = (30-26)/4 = 4/4 = 1
x=1 , y=13
Answer:
m<4 = 117 degrees
Step-by-step explanation:
Knowing that angle 1 is 63 degrees, we can look at the other angle on the same side of the line, angle 4.
Angles on one side of a line add to 180 degrees.
180 - 63 = 117
Answer:
During cool or cold weather episodes, fuel must be consumed to make buildings comfortable living spaces. A useful indicator of fuel consumption for heating purposes is the determination of heating degree-days. They are calculated by accumulating one heating degree-day (HDD) unit for each Fahrenheit degree the daily mean (average) temperature is below the base value of 65°F (18°C). For example, a day with a maximum temperature of 60°F and a minimum of 40°F has a mean temperature of 50°F. Subtracting 50 from 65 yields 15 heating degree-day units for that day. Hence, a day with a high temperature of 45°F and a low of 25°F produces ______ HDDs.
