Answer:

Step-by-step explanation:
The question is not correct (particularly the expression for the area)
A=2lh+2wh
Now we are expected to solve for l, that is we are going to make l subject of the formula, we have
let us take the second term on the RHS to the LHS

we can now divide both sides by 2h we have

hence the expression for the length is 
Given:
ratio of altitude height = 2/3
Required:
ratio of volume
Solution:
Assuming that the only difference that the cylinders has is the height, we can solve for the ratio of the volume.
The volume of a cylinder is equal to πr²×height.
ratio of volume = πr²×2/πr²×3
We cancel the pi and the r² since we assume that the cylinders have the same radius.By cancelling, we are left with:
ratio of volume = 2/3
Given:
Bobby put 1/3 of his lawn mowing money into his savings
He uses the remaining 2/5 to buy a video game.
He has $12 left.
To find:
The amount did he have at first.
Solution:
Let x be the initial amount.
Bobby put 1/3 of his lawn mowing money into his savings. So, the remaining amount is

He uses the remaining 2/5 to buy a video game. Then the remaining amount is





It is given that the remaining amount is $12.



Divide both sides by 2.


Therefore, Bobby have $30 at first.
y - y₁ = m(x - x₁)
y - (-1) = 4[x - (-3)]
y + 1 = 4(x + 3)
y + 1 = 4(x) + 4(3)
y + 1 = 4x + 12
- 1 - 1
y = 4x + 11
The answer is B.
Remember that cents has a decimal when put in an equation.
250(x + 11) + 250x = 4250
250x + 2750 + 250x = 4250
500x + 2750 = 4250
500x = 1500
x = 3 cents (pencils)
x+11 = 14 cents (pens)