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olga2289 [7]
3 years ago
6

Given: f(x) = X2 - 3 and g(x)= x+1 The composite function g.f is

Mathematics
2 answers:
lianna [129]3 years ago
8 0
The answer is c. . .
Minchanka [31]3 years ago
7 0

Answer:

option (c)

Step-by-step explanation:

g.f= g(f(x))

= g(x2 -3)

= (x2 -3)+1

=x2 -2

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Consider the parabola r​(t)equalsleft angle at squared plus 1 comma t right angle​, for minusinfinityless thantless thaninfinity
kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

                                  < at^2+1,t>\cdot < 2at,1>=0

< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




6 0
3 years ago
What is the volume of this cube?
Charra [1.4K]

Answer:

50

Step-by-step explanation:

im not that sure sorry

8 0
3 years ago
Simplify: (5x2 - 4x + 7) – (2x2 – 3x – 4)
Kamila [148]
The answer is b. Hope this helps!!

4 0
3 years ago
find a common denominator for the pair of fractions. then write equivalent fractions with the common denominator. using the comm
liubo4ka [24]

EXPLANATION

Given the fractions:

1/8 and 3/7

In order to find the Common denominator we need to apply the prime factorization as follows:

Prime factorization of 8: 2*2*2

Prime factorization of 7: 7

Multiply each factor the greatest number of times it occurs in either 8 or 7:

= 2*2*2*7

Multiply the numbers: 2*2*2*7 = 56

So, the common denominator is 56

6 0
1 year ago
I need a, b, and c. I don’t quite understand this.
Stels [109]

9514 1404 393

Answer:

  a) y = (x -4)² -4

  b) (4, -4)

  c) translated 4 right, 4 down

Step-by-step explanation:

a) Apparently "graphing form" is a reference to "vertex form." That form is ...

  y = a(x -h)² +k . . . . . . parabola with vertex (h, k) and vertical scale factor 'a'

The coefficient of x² in your given equation is 1, so a=1. The values of h and k can be found as follows.

'h' is the opposite of half the x-coefficient in your equation, so is h = -(-8/2) = 4. The value of k is the square of h, subtracted from the constant in your equation: k = 12 -h² = 12 -16 = -4. (This applies when a=1, as here.) These calculations are the "cut to the chase" version of "completing the square."

The method of "completing the square" has you consider the x-terms separately from the constant term:

  y = (x² -8x) +12

To "complete the square", you want to make the terms in parentheses be a perfect square trinomial. You do that by adding the square of half the x-coefficient. In order to keep the same equation, you need to subtract an equivalent amount outside parentheses:

  y = (x² -8x +(-8/2)²) +12 -(-8/2)² . . . . . add and subtract (-8/2)²

  y = (x -4)² +(12 -16)

Then the vertex form is ...

 y = (x -4)² -4 . . . . and the vertex is (h, k) = (4, -4).

The graphing calculator plot attached confirms this vertex value.

__

The problem statement tells you that you can also find this form by averaging the x-intercepts. If you factor your equation, you get ...

  y = (x -6)(x -2)

The x-values that make these factors zero {6, 2} are the x-intercepts. Their average (6+2)/2 = 4 is the x-coordinate of the vertex (h). You can find the y-coordinate of the vertex by evaluating y when x=4: y = 4² -8·4 +12 = -4. So, the vertex by this method is (h, k) = (4, -4), and the equation in graphing form is ...

  y = (x -4)² -4 . . . . as above.

__

b) As we saw above, the vertex coordinates are (h, k) = (4, -4).

__

c) The vertical scale factor 'a' is 1, so the only transformation done on the graph is to move the parent vertex (0, 0) to the location (4, -4). That is, the graph has been translated 4 units right and 4 units down. (In the attached, the parent function is shown with a dashed line.)

8 0
3 years ago
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