<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B5%7D%7B7%7D%20%20%5Ctimes%20%20%5Cfra

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3 years ago

c%7B4%7D%7B5%7D%20%5Ctimes%20%20%5Cfrac%7B3%7D%7B4%7D%20%20" id="TexFormula1" title=" \frac{2}{3 } \times \frac{5}{7} \times \frac{4}{5} \times \frac{3}{4} " alt=" \frac{2}{3 } \times \frac{5}{7} \times \frac{4}{5} \times \frac{3}{4} " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

VikaD [51]3 years ago

5 0

Answer:

$\frac{2}{3}*\frac{5}{7}*\frac{4}{5}*\frac{3}{4}\\=\frac{2}{7}$

Step-by-step explanation:

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1. Mary is making a necklace by alternating red, yellow, and green beads. In

Feliz [49]

Answer: 20/ 60 = 1/3

Step-by-step explanation:

60 beads in total which makes that the denominator and how many red beads in the numerator (20) then just reduce the fraction

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3 years ago

if the function g is defined by g(x)= {x/2+5 x<7 -3x+3 x >_ 7 what is the average rate of change of g over the interval 4&

OLEGan [10]

Average rate of change = [(g(7) - g(4))/(7 - 4) + (g(8) - g(7))/(8 - 7)] = [(7/2 + 5) - (4/2 + 5)]/(7 - 5) + [(-3(8) + 3) - (-3(7) + 3)]/(8 - 7) = [(8.5 - 7)/2 + (-21 - (-18))/1] = (1.5/2 + (-3)) = 0.73 - 3 = -2.25

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3 years ago

Please help this is due today and I can't figure it out!!!<br>Also explain your answer.

Tasya [4]

Answer:

Ratio (red to blue ) of the perimeters: $\frac{11}{6}$

Ratio (red to blue ) of the areas: $\frac{121}{36}$

Step-by-step explanation:

In similar figures

The ratio between their corresponding sides equal to the ratio between their perimeters

The square the ratio between their corresponding sides equal to the ratio between their areas

Let us solve the question

∵ The red figure and the blue figure are similar

∴ Their corresponding sides have equal ratios

∵ Two corresponding sides are 11 and 6

∴ The ratio of similarity (red to blue) = $\frac{11}{6}$

→ By using the first rule above

∵ The ratio of their perimeters = the ratio of the corresponding sides

∴ The ratio of their perimeters (red to blue) = $\frac{11}{6}$

∴ Ratio (red to blue ) of the perimeters: $\frac{11}{6}$

→ By using the second rule above

∵ The ratio of their areas = Square the ratio of their sides

∴ The ratio of their areas (red to blue) = ( $\frac{11}{6}$ )²

∴ The ratio of their areas (red to blue) = $\frac{121}{36}$

∴ Ratio (red to blue ) of the areas: $\frac{121}{36}$

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