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lara [203]
3 years ago
6

In circle P, if the radius is 3 cm, what is the length of arc AD?

Mathematics
1 answer:
umka21 [38]3 years ago
8 0

Hello there.

We have for a circle that:

\ell=\alpha r

Where:

\ell is the measure of the arc

\alpha is the measure of the angle (radians)

r is the radius of the circle


In our case, we have \alpha = 120^\circ = \dfrac{120}{180}\pi = \frac23\pi ~rad

We have r = 3 cm, then:

\ell = (\frac23\pi )(3\ cm)\\ \\ \boxed{\ell = 2\pi~cm}

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Ksivusya [100]

so sorry I don't know

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2 years ago
Find the lowest common denominator of p+3/p2+7p+10 and p5/p2+5p+6
Sunny_sXe [5.5K]
(P+1)(p+2)(p+5) is LCM
4 0
3 years ago
Read 2 more answers
What are the fourth roots of 6+6√(3i) ?
Helen [10]

Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

r = 12

∅ = arctan 6√3/6

∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4  = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

8 0
3 years ago
I WILL GIVE BRAINLIEST FOR Correct Answer
VladimirAG [237]
Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.

in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1 

in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft

in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft

the answer part 1) BC is 17491 ft

Part 2) Find CD, the height of the plane from the ground, to the nearest foot.

CD=sin24*BD        ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft

the answer part 2)  CD is 6499 ft
4 0
3 years ago
Read 2 more answers
What is the solution of two thirds x=12
joja [24]
Hi there!

To solve this problem, we need to simplify. 

2/3x = 12

To isolate x, we should multiply both sides of the equation by the reciprocal of 2/3 to make x equal to a value:

Reciprocal of 2/3 = 3/2

x = 12 * 3/2
x = 18 

Hope this helps!
8 0
3 years ago
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