Answer:
hello :
90 = 15×6
75 = 15× 5
highest common factor of 90 and is 15 because highest common factor of 5 and 6 is 1
90 = 3² ×2×5
75= 5^3
common multiple of 90 and 75 is : 3²×2×5² = 450
90 and 75 both smaller than 100.
Answer:
About 40 Minutes, Or something close to that
Step-by-step explanation:
The car covers 60 km in 90 minutes or its speed = 60 km*60/90 min = 40 km/hr . So to cover 100 km at the same speed it will take 100/40 = 40 Min
the answer is $34. 36 if I understood your question correctly.
Answer:
B
Step-by-step explanation:
At at least one die come up a 3?We can do this two ways:) The straightforward way is as follows. To get at least one 3, would be consistent with the following three mutually exclusive outcomes:the 1st die is a 3 and the 2nd is not: prob = (1/6)x(5/6)=5/36the 1st die is not a 3 and the 2nd is: prob = (5/6)x((1/6)=5/36both the 1st and 2nd come up 3: prob = (1/6)x(1/6)=1/36sum of the above three cases is prob for at least one 3, p = 11/36ii) A faster way is as follows: prob at least one 3 = 1 - (prob no 3's)The probability to get no 3's is (5/6)x(5/6) = 25/36.So the probability to get at least one 3 is, p = 1 - (25/36) = 11/362) What is the probability that a card drawn at random from an ordinary 52 deck of playing cards is a queen or a heart?There are 4 queens and 13 hearts, so the probability to draw a queen is4/52 and the probability to draw a heart is 13/52. But the probability to draw a queen or a heart is NOT the sum 4/52 + 13/52. This is because drawing a queen and drawing a heart are not mutually exclusive outcomes - the queen of hearts can meet both criteria! The number of cards which meet the criteria of being either a queen or a heart is only 16 - the 4 queens and the 12 remaining hearts which are not a queen. So the probability to draw a queen or a heart is 16/52 = 4/13.3) Five coins are tossed. What is the probability that the number of heads exceeds the number of tails?We can divide